GRE exam question
If the radius of a circle is decreased by 50%, find the percentage decrease in its area. A) 55% B) 65% C) 75% D) 85%
- Sweety
- 12 Jul
- 47 Answers
47 Answers
47 Answers
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Let r1 = 100
Then r2 = 50
A1 = π × 1002 = 10000π
A2 = π × 502 = 2500π
Decrease in area = 10000π - 2500π = 7500π
Percentage decrease in area = 7500π×10010000π=75%0Modal content
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750Modal content
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750Modal content
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750Modal content
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let's suppose area of circle is 3.142×r^2 then after radius is reduced by 50% then area of new circle will be 3.142*0.5r*0.5r=3.142*o.25*r^2 Percentage decrease= ((3.142*r^2-3.142*0.25*r^2)/3.14*r^2 )*100% =((1-0.25)/1)*100% =0.75*100% 75%0Modal content
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c0Modal content
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A1=A A2=.5*.5A=0.25A A1-A2=.75 .75*100=75%0Modal content
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C0Modal content
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C0Modal content
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C0Modal content
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750Modal content
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750Modal content
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75%0Modal content
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750Modal content
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750Modal content
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c0Modal content
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