If the number 3072 is divisible by both 6 and 8, find
The number 3072 is divisible by both 6 and 8, Find the first integer larger than 3072 that is also divisible by both 6 and 8?
- Vansha
- 24 Mar
- 6 Answers
6 Answers
6 Answers
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Required number = Given number + LCM(6,8) = 3072 + 24 = 30960Modal content
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30960Modal content
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LCM of 8 and 6= 24
3072+24=3096
So first number divisible is 3096 by both 6 and 80Modal content
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3096 as 3072+24=3096
as lcm of 6 and 8 is 240Modal content
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Any number divisible by both 6 and 8 must be a multiple of the least common multiple of the two numbers, which is 24.
Hence, any such number can be represented as 24 n .
If 3072 is one such number and is represented as 24n, then the next such number should be 24(n+1)=24n+24=3072+24= 3096.0Modal content
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Answer is 3096-1Modal content
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