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energy of h-atom in the ground state is -13.6 ev ,hence energy in the second excited state is 1)-3.4ev 2)6.4ev what is the ans explain it
energy of h-atom in the ground state is -13.6 ev ,hence energy in the second excited state is 1)-3.4ev 2)6.4ev what is the ans explain it
ans it
Jayati
19 Dec
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Rahul
19 Dec
-3.4
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Shaheen
02 Apr
3.4
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Deepak
15 Mar
1
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Pooja
08 Dec
the answer is -3.4 as,E=Eo/n^2, where n=no. of hydrogen atoms i.e. 4 ,Eo=energy at ground state and E=energy at excited state
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Neeraj
07 Dec
-3.4 bcz The formula is E=-13.6Z/n^2
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Jayati
21 Jul
ans is 1.51ev but explain it
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neeraj
shantanu
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