# Find the missing number in the series: 2, 5,__ , 19 , 37, 75

1. 10 2. 9 3. 7 4. 8

1016 उत्तर
1-20 of  1016
1016 उत्तर
• 9
0

• 9
0

• 9
0

• 7
0

• 7
0

75 previous number is 37 so 37*2+1=75
37 previous number is 19 so,19*2-1=37
assume 19 previous number is x:
19 previousnumber is x so x*2+1
by substitute the given options in x
1.10*2+1=21(is not the next number)
2.9*2+1==19(is the next number)
3.3*2+1=7
4.8*2+1=17
so the option 2 is correct bcz  x of next number is 19

0

• 9 because in this series the order is that even term is double of first term plus 1 and odd term is double of second term minus 1 so following this series we get the unknown no by 2×2+1=5 5×2-1=9 9×2+1=19 so the answer is 9.
0

• 9
0

• 9
0

• 9
0

• 2*2=(4)+1=5 5*2=(10)-1=9 9*2=(18)+1=19 if u do it alternatively,you will get remaining numbers
0

• 2*2=(4)+1=5 5*2=(10)-1=9 9*2=(18)+1=19 if u do it alternatively,you will get remaining numbers
0

• 2*2=(4)+1=5 5*2=(10)-1=9 9*2=(18)+1=19 if u do it alternatively,you will get remaining numbers
0

• 9
0

• 9
0

• 75-37=38, 37-19=18,5+4=9
0

• 9
0

• 9
0

• ans=10 2*2+1=5,2*4+2=10,2*8+3=19,etc
0

• 9
0

अधिक जवाब लोड करें
1-20 of  1016
अन्य संबंधित चर्चाएं
मॉक परीक्षण अभ्यास के लिए
tcs