to what angle a projectile must be projected so that area swept by it is maximum????
this question is of havards entrance which has a level much higher than jee. you will get the answer soon!!!
- Sumit
- 29 जून
- 13 उत्तर
13 उत्तर
13 उत्तर
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jitne degree ka tera deemag hai0Modal content
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ans 45° it's pu 1 4 chapter questions-1Modal content
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45degree0Modal content
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answer is 600Modal content
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450Modal content
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45 degree-2Modal content
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451Modal content
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ans is 45 degree3Modal content
- salman
- sandeep
- ajay
- piyush
- guransh
- montu
- shatabdi
- sandeep
- piyush
- guransh
- montu
- shatabdi
- salman
- ajay
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451Modal content
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45 degree1Modal content
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answer is 45 degree ... based on my analysis.. it is the height the projectile is to reach is to be highest..
Please tell me where u found this harward questions., I want to solve more of these ...2Modal content
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see frnd its just a simple
The relation between the range R
?
on the horizontal plane and the maximum height h
?
reached at td/2
?
is:
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h= R tan(tetha)/4
Now , h = R , at tan (theta ) = 4
Which gives angle as 76° ...
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