A rope 1 cm in diameter breaks if tension in it exceeds 500 N. The maximum tension that may be given to a similar rope of diameter 2 cm is

A) 2000 N B) 1000 N C) 500 N D) 250 N

Deepshikha
14 Mar
97 Answers

97 Answers

- Sweety
- 14 Mar
T = mrw2
T a r
T2/T1 = r2/r1 = T2 = T1 * 2r1 / r1
= 1000 N
- 1 Comment
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archit

smit

ranjan

jeslyn

mwape

bernard

mohit

midhun

shivani

kaviraj.a

archit

smit

ranjan

jeslyn

bernard

mohit

midhun

kaviraj.a

mwape

shivani
- Sher
- 29 Jul
1000
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- PD
  
  PRITISH
- 24 Jul
ratio of areas
(tension prop. to area)
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- AB
  
  Archit
- 23 Jun
2000
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- AA
  
  Aditya
- 23 Jun
1000
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- AS
  
  Anzalnagohar
- 12 Jun
B
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- MS
  
  M
- 07 Jun
B) 1000
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- AU
  
  Anjali
- 06 Jun
B) 1000N
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- SM
  
  Sharmila
- 05 Jun
2000
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- Jayesh
- 05 Jun
1000
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- RM
  
  Rituraj
- 04 Jun
2000
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- Apurva
- 03 Jun
1000N
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- DC
  
  Dhivakar
- 03 Jun
1000
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- SG
  
  Sarvesh
- 03 Jun
1000
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- Auti
- 01 Jun
1000
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- Prashant
- 01 Jun
The answer is A) 2000N Because, This is a question of young modulus and it's formula is - young modulus = (tension*original length)/(cross sectional area*change in length). From the question, we can say that all the quantities except tension and area are constant we can say that tension is directly proportion to area of cros section . thus tension is directly proportion to D²(as area = πD²/4; D is diameter). so if for D = 1 tension=500N then for D =2 tension will be four time i.e. tension=2000N
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- BA
  
  Bernard
- 01 Jun
F1*(d2)^2=F2*(d1)^2 F2=[500*(0.02)^2]÷[(0.01)^2] F2=2000Newtons
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- Abhishek
- 31 May
B) 1000N
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- Midhun
- 31 May
1000
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- Atul
- 31 May
1000N
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