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Shikha
- 01 Jul
The formula is actually better written
ΔS=Q/T.
That is, the change in entropy associated with the flow of heat is inversely proportional to the temperature at which the heat flow occurs. Note that Q is already a change itself: it is not a state variable, but rather something more like ΔW. Physically, this is because adding heat to a hot system doesn't disorder it as much as adding the same heat to a cold system.If T is changing, you would need to integrate
ΔS=∫dS=∫δQ/T
For an ideal gas at constant volume and particle number, it turns out
ΔS∝log(Tfinal / Tinitial).
Thus doubling the temperature does lead to the exponential of S doubling, as you would expect.
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